-4.9x^2+29x+2.8=0

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Solution for -4.9x^2+29x+2.8=0 equation:



-4.9x^2+29x+2.8=0
a = -4.9; b = 29; c = +2.8;
Δ = b2-4ac
Δ = 292-4·(-4.9)·2.8
Δ = 895.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{895.88}}{2*-4.9}=\frac{-29-\sqrt{895.88}}{-9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{895.88}}{2*-4.9}=\frac{-29+\sqrt{895.88}}{-9.8} $

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